quick question, little help please
#1
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quick question, little help please
hey guys i picked up some speakers and an amp and would just like to make sure i'm hooking them up correctly.
its a truck box with three 10' dual voice coil subs(4ohm)
and a kenwood amp that is a four channel bridgeable amp.
this is just a tempory system i just want something to listen to while working on the car.
i in laymens terms .... please help lol i hooked it up bridged with pos and neg going to same on one side of 1st sub then connected same to other side of sub then from that 2nd terminal on the 1st sub went to the sub #2 and repeated... is that right.
i turned it on and the amp kept cutting out and got hot extremely fast so i disconnected it. litteraly on for about a minute and a half.
thanks for any help guys.
brian
its a truck box with three 10' dual voice coil subs(4ohm)
and a kenwood amp that is a four channel bridgeable amp.
this is just a tempory system i just want something to listen to while working on the car.
i in laymens terms .... please help lol i hooked it up bridged with pos and neg going to same on one side of 1st sub then connected same to other side of sub then from that 2nd terminal on the 1st sub went to the sub #2 and repeated... is that right.
i turned it on and the amp kept cutting out and got hot extremely fast so i disconnected it. litteraly on for about a minute and a half.
thanks for any help guys.
brian
#2
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Re: quick question, little help please
Let me make sure I am reading this correctly... you bridged it first, then ran positive from one speaker terminal to the next, and did that for all 6 voice coils? Rather than just say, Ok, you are doing it wrong, let me explain... Heres the issue with that...
When you bridge an amp, that drops the impedance in half right off the bat. If you have a 4ohm speaker and hook it to a bridged amp, the amp "sees" a 2ohm load.
Heres where this story gets worse. Every time you connect 2 voice coils in parallel, you cut the amount of ohms in half. So 2 4ohm speakers wired in parallel is a 2 ohm load. Now, take that 2 ohm load and hook it to a bridged amp and that becomes a 1 ohm load. This is only speaker now with a dual voice coil. you did this 3 times over.
Here is the recommended way to wire this up... 3 dual voice coils, 4 channel amp.
http://a248.e.akamai.net/pix.crutchf..._4-ohm_4ch.jpg
Wire each voice coil in parallel per speaker to create a 2 ohm load, then hook each lead to a separate channel on the amp. That way each channel is only under a 2 ohm load, which wont stress the amp too much.
When you bridge an amp, that drops the impedance in half right off the bat. If you have a 4ohm speaker and hook it to a bridged amp, the amp "sees" a 2ohm load.
Heres where this story gets worse. Every time you connect 2 voice coils in parallel, you cut the amount of ohms in half. So 2 4ohm speakers wired in parallel is a 2 ohm load. Now, take that 2 ohm load and hook it to a bridged amp and that becomes a 1 ohm load. This is only speaker now with a dual voice coil. you did this 3 times over.
Here is the recommended way to wire this up... 3 dual voice coils, 4 channel amp.
http://a248.e.akamai.net/pix.crutchf..._4-ohm_4ch.jpg
Wire each voice coil in parallel per speaker to create a 2 ohm load, then hook each lead to a separate channel on the amp. That way each channel is only under a 2 ohm load, which wont stress the amp too much.
#3
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Re: quick question, little help please
Let me make sure I am reading this correctly... you bridged it first, then ran positive from one speaker terminal to the next, and did that for all 6 voice coils? Rather than just say, Ok, you are doing it wrong, let me explain... Heres the issue with that...
When you bridge an amp, that drops the impedance in half right off the bat. If you have a 4ohm speaker and hook it to a bridged amp, the amp "sees" a 2ohm load.
Heres where this story gets worse. Every time you connect 2 voice coils in parallel, you cut the amount of ohms in half. So 2 4ohm speakers wired in parallel is a 2 ohm load. Now, take that 2 ohm load and hook it to a bridged amp and that becomes a 1 ohm load. This is only speaker now with a dual voice coil. you did this 3 times over.
Here is the recommended way to wire this up... 3 dual voice coils, 4 channel amp.
http://a248.e.akamai.net/pix.crutchf..._4-ohm_4ch.jpg
Wire each voice coil in parallel per speaker to create a 2 ohm load, then hook each lead to a separate channel on the amp. That way each channel is only under a 2 ohm load, which wont stress the amp too much.
When you bridge an amp, that drops the impedance in half right off the bat. If you have a 4ohm speaker and hook it to a bridged amp, the amp "sees" a 2ohm load.
Heres where this story gets worse. Every time you connect 2 voice coils in parallel, you cut the amount of ohms in half. So 2 4ohm speakers wired in parallel is a 2 ohm load. Now, take that 2 ohm load and hook it to a bridged amp and that becomes a 1 ohm load. This is only speaker now with a dual voice coil. you did this 3 times over.
Here is the recommended way to wire this up... 3 dual voice coils, 4 channel amp.
http://a248.e.akamai.net/pix.crutchf..._4-ohm_4ch.jpg
Wire each voice coil in parallel per speaker to create a 2 ohm load, then hook each lead to a separate channel on the amp. That way each channel is only under a 2 ohm load, which wont stress the amp too much.
thanks
brian
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Re: quick question, little help please
Hey no problem. Im 35 myself, and I always forget the labels for series vs parallel. Just glad I was able to help in a way that made sense.
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Re: quick question, little help please
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Re: quick question, little help please
#7
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Re: quick question, little help please
Exactly what I thought was meant, but stated differently.
Here's another explanation of bridging.
Perry rocks!
http://www.bcae1.com/bridging.htm
So, why do people talk about the impedance halving? Well, it's a simple model that isn't correct but is easy to explain to people who don't know what's really going on. It goes like this: When you bridge the amp, each channel is "seeing" half the load presented to the amp. So, if you bridge an amp to 4 ohms, each channel "sees" 2 ohms. Therefore, each channel puts out twice as much power, and the combined output is quadruple a single channel at 4 ohms.
Perry rocks!
http://www.bcae1.com/bridging.htm
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