160°F thermostat
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Joined: Jul 2003
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From: Germany
Car: 91' Camaro
Engine: Carbed 305
Transmission: 5-Speed Manual
160°F thermostat
Hi,
searched the forum already but i didnt found anything.
however, what do i have to change in my eprom to work with the 160°F thermostat? Only the closed loop coolant treshold?
thanks,
nebu
searched the forum already but i didnt found anything.
however, what do i have to change in my eprom to work with the 160°F thermostat? Only the closed loop coolant treshold?
thanks,
nebu
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Joined: Jun 2000
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From: In reality
Car: An Ol Buick
Engine: Vsick
Transmission: Janis Tranny Yank Converter
fan temp enable.
Maybe the TCC enable threshold
Charcoal canister enable threshold
EGR
DFCO
You need to drive the car and see how the above seem.
You maybe fine, but, you might be close enough to the normal enable temps to have the engine chuggle between on and off on between some of them.
Maybe the TCC enable threshold
Charcoal canister enable threshold
EGR
DFCO
You need to drive the car and see how the above seem.
You maybe fine, but, you might be close enough to the normal enable temps to have the engine chuggle between on and off on between some of them.
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Joined: Feb 2004
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From: Munster IN
Car: 92 RS, 05 GTO (sold), 10 TL AWD
Engine: 383 HSR w/DSC1
Transmission: 700r4
Axle/Gears: Strange S60/3.73
I know this is an old thread but I am trying to adjust for a lower t-stat as well. I converted to tpi and have only one fan so is fan 1 the constant I want to change? also what is DFCO? finally what is the conversion eq. for C* to F* the super $8D ecu uses C* for it's values.
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Car: '91 Z28 convertible
Engine: TPI
Transmission: T5
Axle/Gears: 3.27 posi disc
Conversion btw °F and °C involves basic elementary school math.
°C = (°F - 32) / 1.8
°F = °C * 1.8 + 32
°C °F
0 32
5 41
10 50
15 59
20 68
25 77
30 86
35 95
40 104
45 113
50 122
55 131
60 140
65 149
70 158
75 167
80 176
85 185
90 194
95 203
100 212
105 221
110 230
115 239
120 248
125 257
130 266
So for every 5°C increase, there is 9°F increase. Or for everz 10°C increase, there is corresponding 18°F increase.
Hope this helps.
Lou
°C = (°F - 32) / 1.8
°F = °C * 1.8 + 32
°C °F
0 32
5 41
10 50
15 59
20 68
25 77
30 86
35 95
40 104
45 113
50 122
55 131
60 140
65 149
70 158
75 167
80 176
85 185
90 194
95 203
100 212
105 221
110 230
115 239
120 248
125 257
130 266
So for every 5°C increase, there is 9°F increase. Or for everz 10°C increase, there is corresponding 18°F increase.
Hope this helps.
Lou
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