Suspension and Chassis Questions about your suspension? Need chassis advice?

35mm offset?

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Old Apr 15, 2007 | 06:16 PM
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91_5.7_TPI's Avatar
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From: East Tennesse
Car: 1991 RS Camaro
Engine: L03 (want LS1)
Transmission: 700R-4 (and T56)
Axle/Gears: 4th Gen 3.23 posi
35mm offset?

I am considering getting a set of 17x9s that have a 35mm offset. I know that with the 56mm offset (ZR1s, for instance) I would need a 2.25" spacer. With the 35mm, I would need less than that, wouldn't I?
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Old Jun 2, 2007 | 10:42 PM
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BOTTLEDZ28's Avatar
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From: Mass
Engine: 350 TPI
Transmission: A4
Axle/Gears: 3.23
Re: 35mm offset?

Im looking for the SAME answer.
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Old Jun 3, 2007 | 03:50 PM
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From: 39.84N 105.11W
Car: '89 Trans Am GTA
Engine: WAS 350 - now L92 (alum. 378/6.2L)
Transmission: WAS 700R4, now a built T56
Axle/Gears: 3.27 9-bolt
Re: 35mm offset?

If you're looking to find what the spacer width would be to put the wheel in the same place, the math is pretty simple (ya just have to go back to algebra class).

First, you define it like so:

Code:
36      x
---  =  ---
56     2.25
You can see that I put the values for the wheel offsets in the first fraction, & the one known value for the spacer in the second one, with "x" representing the unknown spacer value. To solve for x, you just multiply diagonally (36 x 2.25), & then divide by the remaining number, the result is your answer. So...

(36 x 2.25) / 56 =

81 / 56 =

a 1.4464285714285714285714285714286" spacer. (I'd guess that 1.5" would be pretty close...)

This isn't the only way that you can define the problem, you can also have the values for the wheel offsets horizontally across from each other (either on the top or the bottom of each fraction), but then you'd have to have the '2.25' as the other half of the '56' equation.

In a nutshell, it's "multiply diagonally {the 'x' helps to remember that}, then divide by the remaining number".

The one absolute rule is that you cannot have the two known values diagonally apart, they have to be in either a horizontal or vertical line from each other. (Yes, I know that it can be solved if they're diagonally separated, but this formula makes it easy to remember, OK??)

And no, I'm not some kind of math whiz, it's just that I've found this formula to be massively useful for me, so I've used it a lot & it's stuck with me!

Hope this helps.

Last edited by V8Rumble; Jun 3, 2007 at 04:01 PM.
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