Fan?
Joined: Mar 2000
Posts: 43,187
Likes: 42
From: Littleton, CO USA
Car: 82 Berlinetta/57 Bel Air
Engine: L92/LQ4 (both w/4" stroke)
Transmission: 4L80E/4L80E
Axle/Gears: 12B-3.73/9"-3.89
There was a flexible duct going up by the alternator, then a formed rigid duct that took air underneath the air cleaner to blow on the carb. It clipped on the fuel line nut and had a clamp to the alternator bracket.
The idea was to keep the carb a little cooler while the engine was hot and not running to reduce vapor lock. The fan has its own thermal switch in the return heater hose (at least mine does).
The idea was to keep the carb a little cooler while the engine was hot and not running to reduce vapor lock. The fan has its own thermal switch in the return heater hose (at least mine does).
Joined: Sep 2007
Posts: 598
Likes: 2
From: Hampton, Virginia
Car: 87 Camaro Z-28
Engine: 305 LG4 w/ E4ME carb
Transmission: 700R4
Axle/Gears: 2.73
Re: Fan?
I want to make sure I have vapor lock straight. Since using a different carb (but very similar E4ME carb), when my car has really been driven and warmed up, then up to an hour or even two later it doesn't star. no click. nothing. did this several times during last month. battery checked good. added a blanket to protect the starter from heat but it almost did it again on Sunday. Is this vapor lock?
Joined: Sep 2007
Posts: 598
Likes: 2
From: Hampton, Virginia
Car: 87 Camaro Z-28
Engine: 305 LG4 w/ E4ME carb
Transmission: 700R4
Axle/Gears: 2.73
Joined: Mar 2000
Posts: 43,187
Likes: 42
From: Littleton, CO USA
Car: 82 Berlinetta/57 Bel Air
Engine: L92/LQ4 (both w/4" stroke)
Transmission: 4L80E/4L80E
Axle/Gears: 12B-3.73/9"-3.89
Vapor lock http://en.wikipedia.org/wiki/Vapour_lock (obtained by a 10-sec Google search)
Starter problems have to do with the electrical properties of copper. The hotter it gets, the higher the electrical resistance. Since the starter operates on the electromagnet principle, where the magnetic field is a function of current, and higher resistance reduces the current for a given voltage (V = IR, or I = V/R where "I" = current), a hot starter will not work as well as a cool one.
Starter problems have to do with the electrical properties of copper. The hotter it gets, the higher the electrical resistance. Since the starter operates on the electromagnet principle, where the magnetic field is a function of current, and higher resistance reduces the current for a given voltage (V = IR, or I = V/R where "I" = current), a hot starter will not work as well as a cool one.
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