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Questions on Reading info on FAST Data logger

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Old Apr 3, 2005 | 10:44 AM
  #1  
The Man's Avatar
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Questions on Reading info on FAST Data logger

My friends 67 camaro(Turbo SBC 91mm) was tuned by Youngs Performance(safe tuned). We decided to start loggging some passes last night. We are not sure how much boost we are running...(he does have time to look at the gauge). We are not running alot...we ehave the boost controller turn very low.
On the data logger we record a pass and was watching everything and the AF was 10.1 and timing 20* but the only thing We could use to figure out the boost is the MAP(it is a 3bar)...but(something isn't adding up) during the pass the map was reading 63-67kpa's. I thought a 3 bar was 0-300kpa if so I wonder what is going on. I know at the line with the trans brake we are getting about 10-12lbs of boost. He has the sequential with Wideband O2.

What should the kpa's be and how do you convert kpa's to boost?
Thanks
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Old Apr 3, 2005 | 01:37 PM
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From: Chasing Electrons
Car: check
Engine: check
Transmission: check
If the MAP on the logger was actual boost, and not KPa absolute, then it looks OK. The conversion from KPa to psi is:

psi = KPa / 6.883

RBob.
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Old Apr 3, 2005 | 01:42 PM
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From: In reality
Car: An Ol Buick
Engine: Vsick
Transmission: Janis Tranny Yank Converter
Re: Questions on Reading info on FAST Data logger

Originally posted by The Man
during the pass the map was reading 63-67kpa's. I thought a 3 bar was 0-300kpa if so I wonder what is going on.
Is the vacuum line going to the MAP spliced into some thing?.

You have to run a dedicated line for the MAP. Plus is should be hard line for as much of the lenght as possible, and as short as possible.

Here's what I've done. This way there's no possibility of something being wrong, other then a sensor failing.

http://www.t6p.com/forums/showthread.php?t=5967

Last edited by Grumpy; Apr 3, 2005 at 01:44 PM.
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Old Apr 4, 2005 | 07:19 AM
  #4  
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From: NE, Texas
map

I believe the map has its own metal line with nothing else on it. Thanks for your help.
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Old Apr 4, 2005 | 07:26 AM
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formula

Don't you have to subtract 14.7 from the answer to get boost?

psi = (KPa / 6.883)-14.7

Thanks
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