I brought my 89 350 TPI block to a machine shop and he said it would be a good idea to bore it .030" over. What would the displacment be? Thanks.

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1984 Camaro Sport Coupe - 73K Miles
5.0 Carbed LG4
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Coming Soon:
350 TPI
Complete 3" Exhaust System
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3.27 Disc Brake Posi Rear

 

Approximately 355ci.

 

355

 

Ok, thanks.

 

No real intent to flame, but this is junior high math.

Volume of a cylinder = area of the base times height.

For an engine, the area of the base = bore, height = stroke. This is the volume displacement, as it's called.

Area of circle = pi times radius squared, or pi x diameter / 4 (pi ~ 3.14159)

For a 350, the standard bore is 4.000". Bored .030" over, it's 4.030. 4.030 squared divided by 4 = 4.060225. Times pi = 12.7556.

The stroke of a 350 is 3.48", so above times that = 44.3894 cubic inches. That's the volume displacement of each cylinder, and there are 8 of them, so the total displacement is 355.11 cubic inches.

Approximately.

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82 Berlinetta, orig V-6 car, now w/86 LG4/TH700R. 2.93 limited slip. Cat-back from '91 GTA, Accel HEI SuperCoil. AMSOIL syn lubes bumper-to-bumper. Daily driver, work-in-progress (LG4 w/LB9 block, ZZ3 cam and intake, WP 305 heads ported & polished, Hooker headers & y-pipe, hi-flow cat).
57 Bel Air, my 1st car. 0.030 over 396, Weiand Action+, Edelbrock 1901 Q-Jet, Jacobs Omnipack, 1-3/4" headers, TH400 w/TCI Sat Night Special conv & shift kit, 3.08 10-bolt, AMSOIL syn lubes bumper-to-bumper. Best 15.1 @ 5800' Bandimere. Daily driver while Camaro was being put together.

 

If I have a circle that has a 2" diameter.

So the area should be radius square * pi.
I'm coming up with PI. 1 square = 1 * pi = pi
Now with your formula (pi x diameter /4) I'm coming up with 1.57 ???

Ron

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'82 Trans Am
'81 Camaro Z-28
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