What is a general formula for higher speed acceleration, ex. 60-90mph accels. In regards to engine and gearing. Thank you.

 

((MPH * gear ratio *336) / tire diameter) = RPM

For example if you have 3.23:1 rear gears and you are in 2nd gear your ratio is 3.23 * 1.62.
So if you have 25" tall tires it looks like this.

((60mph * 5.23 *336) / 25) = 4220 RPM engine speed

I think the idea will be to maximize engine power when you are in that RPM range,
or shift the RPM range so you are at maximum power at those speeds.

Have you tried a carburetor?

 

What are you using for a chip. I hope it is custom burned by you for your car, not some mail order one.

The performer is choking your engine somewhat. The cam is most likely the biggest bottleneck though.

At 60 mph my 2nd gear puts the tach at 3,500 rpm, it is just reaching 95 mph when mine shifts 2-3 @ 5,500. For being a 5,000+ lbs brick with a 245 RWHP 305, not as many cars as you would think, can stay with it from 60-90. Numerous imports have tried, but not many have pulled ahead. Generally when I mash it, hit 2nd and pull a car length or two in about 2 seconds they shut it down and quit trying.

All I can say is have your car geared so that you run from peak torque to peak horsepower in the given speed band. Say you want to do good 20 punches. Gear your car to run at peak torque in 1st gear at 20 mph, then have your 2nd or 3rd gear at your end. This typically runs from about 20-100 really well.

My peak torque is at 3,000 RPM and my peak HP is now at 5,600 rpm.

With the 3.06 first gear of the 700r4, 3.08 gear, and 2,000 stall mine leaps from a 20 punch. The engine is turning about 2,200 rpm (a little below peak torque but acceptable) in 1st, spins to 5,500 (50 MPH), drops to 2nd and about 3,000(peak torque), then climbs back to 5,500 (95 MPH). The whole endeavor takes about 15 seconds.

I could imagine what a 1,300+ lbs lighter F-body would do, when setup the same way.