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Linear increase with HP and TQ

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Old Mar 17, 2007 | 10:49 AM
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Linear increase with HP and TQ

Why doesn't torque increase linearally with horsepower?

Case in point. DD2000.

I started with 245hp and 345tq
Now I have 483hp and 497tq

Why did hp go up 238 yet tq only went up 152?
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Old Mar 17, 2007 | 11:06 AM
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Are those peak numbers?
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Old Mar 17, 2007 | 11:09 AM
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Yes.
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Old Mar 17, 2007 | 11:31 AM
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From: Mercedes Norte, Heredia, Costa Rica
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Axle/Gears: 3.54 Dana 44
You can't really expect a linear relationship when you're comparing values at two different points on the curves.
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Old Mar 17, 2007 | 02:28 PM
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Horsepower = torque times RPM divided by 5252. If you input a cam that operates in a higher RPM band than your base engine, for instance, torque may be higher but it is also occurring at a higher RPM. So, there are two factors raising horsepower, not just one.
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Old Mar 19, 2007 | 04:45 PM
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Originally Posted by Apeiron
You can't really expect a linear relationship when you're comparing values at two different points on the curves.
Okay. At the same point, peak useable hp, I have 483hp and 461tq. This is at 5500 RPM. My hp surpassed my tq. I wonder what the dyno test looks like on a stock 92 5.7l TPI.
----------
Originally Posted by five7kid
Horsepower = torque times RPM divided by 5252. If you input a cam that operates in a higher RPM band than your base engine, for instance, torque may be higher but it is also occurring at a higher RPM. So, there are two factors raising horsepower, not just one.
Isn't hp a byproduct of torque?

Last edited by Viprklr; Mar 19, 2007 at 04:46 PM. Reason: Automerged Doublepost
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Old Mar 19, 2007 | 04:49 PM
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can you post up the torque and HP curves for your base engine and newly cammed engine?
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Old Mar 19, 2007 | 04:51 PM
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From: Mercedes Norte, Heredia, Costa Rica
Car: 1984 Z28 Hardtop
Engine: 383 Carb
Transmission: 4L60
Axle/Gears: 3.54 Dana 44
Originally Posted by Viprklr
My hp surpassed my tq.
HP will always surpass torque at 5252 RPM. See five7kid's equation.

Originally Posted by Viprklr
Isn't hp a byproduct of torque?
HP is a product of torque and RPM. See the equation again.
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Old Mar 19, 2007 | 05:04 PM
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I'll have to change all the values back to stock to get a dyno graph of the stock engine. Is there one available online somewhere?

I was only able to take pictures of the graph and table. Unfortunately dd2000 doesn't allow me to do much with it's display besides printing.

I see you are correct at the 5252 Apeiron. Interesting.
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Old Mar 19, 2007 | 05:06 PM
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Here are pics of my screen.
Attached Thumbnails Linear increase with HP and TQ-p3190001.jpg   Linear increase with HP and TQ-p3190004.jpg  
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Old Mar 19, 2007 | 05:14 PM
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Your horsepower and torque do not increase linearly with each other because horspower is a function of torque AND rpm. Were it only a function of torque then they would increase linearly together.
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Old Mar 19, 2007 | 05:23 PM
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From: Mercedes Norte, Heredia, Costa Rica
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Engine: 383 Carb
Transmission: 4L60
Axle/Gears: 3.54 Dana 44
They'll also change linearly at any given RPM, but it doesn't necessarily follow that they have any particular relationship at all at different speeds.
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Old Mar 20, 2007 | 07:14 AM
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If the torque curve of an engine were perfectly flat then the hp curve would increase linearly with increasing rpm. (aside: most electric motors behave that way, even at zero rpm). But a real engine doesn't have a flat torque curve because the cylinder filling isn't uniform with rpm. The choice of camshaft and the acoustics of both the intake and exhaust systems affect the cylinder-filling in an rpm-dependent way as well as in a throttle-angle-dependent way.

So the torque curve isn't flat with rpm, and therefore the graph of hp vs rpm isn't a straight line. With that said, over a moderate range of rpms the torque curve is flat within 10 to 20% (say 1600-4000 rpm) and so the hp will increase nearly linearly in that range. When the cylinder filling becomes really poor (at very low rpms when the camshaft overlap hurts, or at very high rpms when there isn't enough overlap and duration) the torque is greatly reduced, and therefore so is hp.

It's all about imperfect cylinder-filling. Percent cylinder fill is directly proportional to cylinder pressure and therefore torque. The rate that this occurs (in an rpm sense) is (horse)power. If you can follow the thought experiment starting with perfect and then imperfect cylinder filling, you can understand how it affects torque and power. HTH.
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Old Mar 21, 2007 | 08:10 PM
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Re: Linear increase with HP and TQ

Thanks for the explanations. I think i've got it!
Somebody asked me this question last week and I couldn't give him an answer. I guess I just had to find out the answer.
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