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Rod Length??? 5.7 or 6

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Old 05-16-2004, 03:34 PM
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Originally posted by Joshua
If we were to use a 5.7 inch rod and 3.484 stroke as our example you would see that no matter the RPM the distance traveled between let's say 2 degrees to 5 degrees would always be the same. You also know that if the RPM is constant then it takes the same amount of time to travel from 2 to 5 degrees as it would take to travel from 5 to 8 degrees. At higher RPMs the amount of time to travel 1 degree would lessen but being in our case that it's constant it would always be the same amount of time for every degree.
This isnt true. This can be seen easily at TDC or BDC. When the crank position is 4* past TDC, the piston has moved 0.005531" down the bore from its position at 0* (TDC). However, at 94* (the same 4* past the 90 position), the piston moves 0.12138" from the 90* position. The piston does not move the same amount for each degree of rotation of the crank.

These calcs were made using a 3.48" stroke, and a TI-83 calculator.
Old 05-16-2004, 03:47 PM
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I'm saying that the distance between 2 - 5 degrees is the same whether you're traveling at 2000 or 5000 RPM. Yes it is different than the distance between 5 - 8 degrees but my point was that the same goes for 5 - 8 meaning that at ANY RPM the distance traveled between 5-8 or whatever is going to be the same. It's not dependent on RPM.

Edit:
Also in that quote I mentioned time being the same. So in your example while the distances are different the elapsed time is the same. Meaning the latter has a higher velocity.

Last edited by Joshua; 05-16-2004 at 04:07 PM.
Old 05-16-2004, 05:21 PM
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I misunderstood you. You are exactly correct. :hail: :hail:


--Dave
Old 05-08-2006, 11:35 PM
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Old 05-08-2006, 11:52 PM
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