how to determine litre?
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Joined: Apr 2003
Posts: 3,563
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Car: 1991 RS Camaro (Jet Black)
Engine: 95 383 CI (6.3) LT1
Transmission: 95 T-56
Im curious about this also. The LS1 is really a 346 CI right? So why is it marked as a 5.7? Rounding off? or is it really a 5.6 or something.
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From: E.B.F. TN
Car: Tree Huggers
Engine: Do Not
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oh yea, stekman, you might want to keep this handy:
If you use that ^ you would find this.
Granted, way at the bottom of my search, but there nonetheless.
If you use that ^ you would find this.
Granted, way at the bottom of my search, but there nonetheless.
Member
Joined: Sep 2002
Posts: 171
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From: Seattle, WA
I think a LS1 is 349 CI.
Its easier to figure the size than using the search button.
Its just a ratio.
A 305 is 5.0
350 388
---- = ---
5.7 x
x 5.7
--- = ---
388 350
so
x = 5.7(388)/350 Liters
That will give you a close enuf value.
A 302 is a 5 liter because it is rounded off. not because of marketing.
Or go here:
http://www.happy-gods.com/73nova/enginecalculator.html
Its easier to figure the size than using the search button.
Its just a ratio.
A 305 is 5.0
350 388
---- = ---
5.7 x
x 5.7
--- = ---
388 350
so
x = 5.7(388)/350 Liters
That will give you a close enuf value.
A 302 is a 5 liter because it is rounded off. not because of marketing.
Or go here:
http://www.happy-gods.com/73nova/enginecalculator.html
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Supreme Member
Joined: Apr 2000
Posts: 3,187
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From: E.B.F. TN
Car: Tree Huggers
Engine: Do Not
Transmission: Appreciate Me.
Don't any of you guys use the effin' lins people put in their posts?
Anyway... from the link in my previous post up there in the nose-bleed section:
zzzzzz.......
Anyway... from the link in my previous post up there in the nose-bleed section:
Originally posted by Xenodrgn
...Bore Dia^2 * stroke * # of cylinders * .7854
...
...Bore Dia^2 * stroke * # of cylinders * .7854
...
Originally posted by 89BlwnRs
.25*Pi*bore*bore*stroke*#cylinders
or
.7854*bore*bore*stroke*#cylinders
The .7854 is just Pi*.25
.25*Pi*bore*bore*stroke*#cylinders
or
.7854*bore*bore*stroke*#cylinders
The .7854 is just Pi*.25
Originally posted by JP84Z430HP
Or, the volume of one cylinder is found with "pi 'r' squared" multiplied by the stroke. For a 350 that is (2^2 * 3.1419)*3.48 Then multiply by the number of cylinders.
therefore......2*2*3.1419*3.48*8
Or, the volume of one cylinder is found with "pi 'r' squared" multiplied by the stroke. For a 350 that is (2^2 * 3.1419)*3.48 Then multiply by the number of cylinders.
therefore......2*2*3.1419*3.48*8
zzzzzz.......
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Joined: Oct 2002
Posts: 9,067
Likes: 1
From: Saskatoon, SK, Canada
Car: '83 Z28, '07 Charger SRT8
Engine: 454ci, 6.1 Hemi
Transmission: TH350, A5
Axle/Gears: 2.73 posi, 3.06 posi
ci X 16.38 = cc's
(Ex. 350 x 16.38 = 5733cc)
Oh yea... 61ci is 1L... so divide 388 by 61 to get L.
(Ex. 427 / 61 = 7L)
(Ex. 350 x 16.38 = 5733cc)
Oh yea... 61ci is 1L... so divide 388 by 61 to get L.
(Ex. 427 / 61 = 7L)
Last edited by Air_Adam; May 27, 2004 at 10:52 PM.
(if you're smart, you can go backwards and tell me my overbore) 
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