this is a stupid question!!
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this is a stupid question!!
can some one please explain to me what the liters mean like 5.0 or 5.7? I know this is stupid but i don't know.
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From: Randleman,NC,USA
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Metric equivalent of 305ci (cubic inch) and 350ci engines
5.0L (Liter) = 5000cc (cubic centimeters)
5.7L = 5700cc
And so forth.
5.0L (Liter) = 5000cc (cubic centimeters)
5.7L = 5700cc
And so forth.
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And is also measuring displacement. Displacement is basically the total area of what the pistons occupy (bore), including travel (stroke), for each cylinder. Total displacement is including all cylinders.
I forget the exact formula, but there's one out there that will calculate the bore and stroke cubic inch area, then you multiply that by the number of cylinders to get your displacment (in cubic inches). You can then convert it over to metric cc's.
I forget the exact formula, but there's one out there that will calculate the bore and stroke cubic inch area, then you multiply that by the number of cylinders to get your displacment (in cubic inches). You can then convert it over to metric cc's.
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Okay I have it:
( Bore (i.e. 4.000") x Stroke (i.e. 3.500) x 3.1416 (pI) ) x Cylinders (i.e. 8)
(4.000 x 3.500 x 3.1416) x 8 = 351.8592
First set calculates the total area of bore and stroke. Then multiply by number of cyls.
( Bore (i.e. 4.000") x Stroke (i.e. 3.500) x 3.1416 (pI) ) x Cylinders (i.e. 8)
(4.000 x 3.500 x 3.1416) x 8 = 351.8592
First set calculates the total area of bore and stroke. Then multiply by number of cyls.
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The equation is:
(pi * (bore/2)^2) * stroke * 8
It's just the equation for the volume of a cylinder (everyone think way back to geometry) where bore/2 is the radius and stroke is the height. Since you have an eight cylinder engine you multiply it by eight to get the total displacement.
EDIT: Allan, your equation is close but not exact. It's only going to work when (bore/2)^2 = bore.
Try your equation for the 305...
(pi * (bore/2)^2) * stroke * 8
It's just the equation for the volume of a cylinder (everyone think way back to geometry) where bore/2 is the radius and stroke is the height. Since you have an eight cylinder engine you multiply it by eight to get the total displacement.
EDIT: Allan, your equation is close but not exact. It's only going to work when (bore/2)^2 = bore.
Try your equation for the 305...
Last edited by Mark305TBI; Dec 20, 2001 at 01:49 PM.
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To expound:
By law, 1 inch = 2.54 centimeters.
2.54 centimeters cubed is 16.387064 cubic centimeters (or cc's). Since 1 cc = 1 ml, and 1000 ml = 1 liter, 305.19179 cubic inches (the displacement of a 3.736" x 3.48" GM 305 engine) times 16.387064 cc/cubic inch = 5001.1974 ml, or 5.0011974 liters, which is rounded to 5.0 liters.
Ain't math fun?
By law, 1 inch = 2.54 centimeters.
2.54 centimeters cubed is 16.387064 cubic centimeters (or cc's). Since 1 cc = 1 ml, and 1000 ml = 1 liter, 305.19179 cubic inches (the displacement of a 3.736" x 3.48" GM 305 engine) times 16.387064 cc/cubic inch = 5001.1974 ml, or 5.0011974 liters, which is rounded to 5.0 liters.
Ain't math fun?
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Your formulas are right.
But here's the pocket size way of doing them.
bore * bore * .7854 * stroke = CID of ea. cylinder
Multiply by the # of cylinders = total CID
Then on a 'L to CID' and 'CID to L'
Divide CID by 61.4 to get ~L
Multiply L by 61.4 to get ~cid
These are only gonna be close, but you guys know how to round up or down right?
AJ
But here's the pocket size way of doing them.
bore * bore * .7854 * stroke = CID of ea. cylinder
Multiply by the # of cylinders = total CID
Then on a 'L to CID' and 'CID to L'
Divide CID by 61.4 to get ~L
Multiply L by 61.4 to get ~cid
These are only gonna be close, but you guys know how to round up or down right?
AJ
Last edited by AJ_92RS; Dec 20, 2001 at 06:06 PM.
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