Approximately how many degrees is one turn
i'm confussed to, i thought 1 full turn was 360* too.
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ICON Motorsports
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MM Black Diamond 538 F&AM
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ICON Motorsports
1st & 3rd
MM Black Diamond 538 F&AM
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From: PA
Car: 88 Firebird WS6
Engine: 350 TPI
Transmission: T56
Axle/Gears: 3.42
Unless he's talking about crankshaft vs cam degrees. The crankshaft spins 2x faster than the cam, so for every complete turn of the cam, the crank spins twice.
(Had to fix the goof up...)
[This message has been edited by JoelOl75 (edited June 09, 2001).]
(Had to fix the goof up...)
[This message has been edited by JoelOl75 (edited June 09, 2001).]
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From: South Windsor, CT
Car: '89 GTA
Engine: ZZ6TPI
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2pi radians
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89 Transam GTA, 350TPI, auto, 3.27 rear, dual cats, gray.
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89 Transam GTA, 350TPI, auto, 3.27 rear, dual cats, gray.
Magnaflow cat-back,
K&N open element,
Best E.T. 14.63@95mph
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Since (as someone mentioned above but then putzed the conclusion) one full turn of the distributor is 2 full turns of the crank, which would be 720°. During one complete revolution of the dist shaft, #1 TDC occurs twice: once at #1 firing, and once when #1 comes to the top of the exhaust stroke and begins its intake stroke.
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"So many Mustangs, so little time..."
ICON Motorsports
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"So many Mustangs, so little time..."
ICON Motorsports
<font face="Verdana, Arial" size="2">Unless he's talking about crankshaft vs cam degrees. The camshaft spins 2x faster than the
crank, </font>
crank, </font>
<font face="Verdana, Arial" size="2">so for every complete turn of the crank, the cam (and distributer) spins once.</font>
<font face="Verdana, Arial" size="2">During one complete revolution
of the dist shaft, #1 TDC occurs twice: once at #1 firing, and once when #1 comes to the
top of the exhaust stroke and begins its intake stroke.</font>
of the dist shaft, #1 TDC occurs twice: once at #1 firing, and once when #1 comes to the
top of the exhaust stroke and begins its intake stroke.</font>
...TDC in mechanical terms does occur twice per each cam revolution. But, when setting an engine at "TDC", it's #1 piston is set at the compression stroke of the crank when said piston is at mechanical TDC. This is the common term (and engine position) for TDC.Easy terms:
the Cam and Distributor spin ONCE (360°) for every TWO complete rotations of the Crankshaft.
Hence, as the question asks:
1) The distributor rotates a complete circle (360°) for every cam rotation.
2) The distributor rotates half a circle (180°) for one complete crank rotation.
This is getting crazy...Hehehhhh.
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86 Trans Am WS6 Black with tinted windows, ZZ4, Mini-ram, true duals, LT4 HotCam, AFR 195 heads.
***Too many other mods to mention***
"In the future, cities will become deserts,
roads will become battlefields, and the hope of mankind
will appear as a stranger" The Road Warrior
Or if you have Calculus on the brain: for every 2Pi radians turn of the distributor you have 4Pi radians turns of the crank. Sorry, have been in Cal 3 class all day and I want somebody else to suffer with me. 
bsa

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